ElectEngEx1

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Ok, here's my first Electrical Engineering Problem example. It is closely related to the types of physics circuits problems on the Differential Equations table.

Using Kirchhoff's Voltage Law (KVL), Kirchhoff's Current Law, and Ohm's Law solve the circuit below.

First identify that there is a voltage source Vs, a current controlled current source, a 5 ohm resistor in the first branch, and a 3 ohm resistor in the final branch. There is a known voltage of 20V over the output resistor as well.

Our first step is to use Ohm's law to solve for the iy in the output branch: iy = Vo/R = 20V/3 ohms = 6.7 A.

Next using KCL at top end of controlled source we find ix = 5.13 A.

Then we find Vx = ix * R in the first branch Vx = 25.64V

Finally applying KCL around the periphery:

Vs = Vx + 20 = 25.64 V + 20 V = 45.64 V

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